Re: DS2: Design questions of my own.

Uh, yeah, sure.... I'll take both you at face value (Doublespeak works,
George!)

Bigger guns kill things "better."  That I understand...

Gracias,
Glenn/Triphibious@juno.com
This is my Science Fiction Alter Ego E-mail address.
Historical - Warbeads@juno.com
Fantasy and 6mm - dwarf_warrior@juno.com

On Thu, 17 Jan 2002 15:27:47 -0700 "B Lin" <lin@rxkinetix.com> writes:
>The difference here is the usage of %.
>
>The point I was making was the % chance of kill was increased by 25, 
>thus 25% increase.
>
>You are using % as a factorial increase - 50% increase over the 50% 
>baseline.
>
>Since there is an absolute limit to % kill, it makes more sense to use 
>100% kill as the baseline and count absolute, not relational increases 
>- so a 25% increase means 25 more percent chance to kill compared to a 
>100% chance to kill rather than using a fractional description.
>
>If a weapon system was listed as being 500% better than another for 
>only an increase of 50% mass it would sound good.
>
>Or would it be easier to rate if you stated that it increased the kill 
>percentage by 16% for a cost of 2 mass?
>
>Does it still sound as good if you find out it has an overall 20% 
>chance of kill for 6 mass?
>
>Your usage depends on what number you are using for a baseline.  As 
>your baseline increases in value, the apparent value of the increases 
>goes down (i.e. 10 points compared to 10 points is 100%, but compared 
>to 50 is only 20%)  When rolling % dice, what is important is that it 
>is a 10 point or 10% difference, not that it is 10% depending on the 
>baseline.
>
>I don't disagree that MDC/5 is a better buy, just in how much of a 
>better buy.
>
>The use of mass % is faulty for the same reason, as you get to larger 
>and larger masses, the amount a single unit counts towards the 
>percentage change decreases.
>
>You can accurately compare Kill% to mass if you assume each item you 
>are comparing starts with the same mass.
>
>Your calculation below is a correct way to compare systems - a %kill 
>rate to a single mass unit.  In the case below you fixed the kill rate 
>to 75%.
>
>--Binhan
>
>> -----Original Message-----
>> From: Brian Bilderback [mailto:bbilderback@hotmail.com]
>> Sent: Thursday, January 17, 2002 3:01 PM
>> To: gzg-l@csua.berkeley.edu
>> Subject: RE: DS2: Design questions of my own.
>> 
>> 
>> B Lin Wrote:
>> 
>> >Actually the better number is 25%
>> >
>> >Chance of absolute kill is increased from 50% to 75%, an 
>> increase of 25%.
>> 
>> Actually, the % increase is based on the number it's 
>> increased from  that's 
>> the way you calculate increases.  75% is 25 greater than 50%. 
>>  25 is 50% of 
>> 50, so the increase is 50%.
>> 
>> >Saying that it is an increase of 50% in chance to kill is a little 
>> >misleading.
>> 
>> I never realized that accepted standard methods of 
>> calculating increases was 
>> misleading....
>> 
>> >An obvious example would be an increased kill probability 
>> from 1% to 5%, 
>> >the increase is 500% by your accounting, but in game terms, 
>> the increase is 
>> >only 4%.
>> 
>> Not just by my accounting, 4 IS a 400% increase over 1 - 
>> whether we're 
>> talking about 1$, 1%, 1 egg, 1 Narn....
>> 
>> >Conversely a weapons system that already has a 75% kill rate 
>> compared to 
>> >one that has 100% kill rate - according to your usage, the 
>> 100% weapon 
>> >would ONLY have an increase of 33%.
>> 
>> Which is the correct usage.	Especially since we're comparing 
>> killability to 
>> capacity.  If the capacity of an MDC 5 is 25% greater than an 
>> MDC 4 (15 is 
>> 25% more than 12, 10 is 25% more than 8), we have to use the 
>> same formula on 
>> the kill % increase.
>> 
>> Let's do it this way: (I may not be up in the technical ken 
>> of the rest of 
>> the group, but I do remember my basic algebra)  Let's go with 
>> the 50% and 
>> 75% kill chances, and the 12 capacity for a turreted MDC 4.	How 
>many 
>> capacity would the MDC 5 be if it's Capacity-to-kill ratio 
>> was the SAME as 
>> the MDC 4?  Lets see....
>> 
>> 50/75=12/x
>> 
>> 50x=12(75)
>> 
>> 50x=900
>> 
>> x=18
>> 
>> So an MDC 5, to cost as much in capacity in relationship to 
>> it's kill ratio 
>> as the MDC 4, would need to take up 18 capacity.  But it 
>> takes up only 15.
>> 
>> I'd call that a bargain - the best I ever had.
>> 
>> Brian B2
>> 
>> 
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