Re: Crowbars
From: Nyrath the nearly wise <nyrath@c...>
Date: Mon, 12 Jun 2000 19:27:08 -0400
Subject: Re: Crowbars
"Izenberg, Noam" wrote:
> You'd have to generate convincing PSB of an antimatter containment
system
> that wouldn't consume and broadcast enough energy to give significant
> advanced warning.
Well, it depends on how FTL works in Full Thrust.
The basic book says that "the forces generated by FTL
drive units are very powerful and result in spatial
distortions that can be highly dangerous in close proximity
to any other mass, including other ships."
It does not give enough detail to judge how much damage
will be inflicted on ship/missile X when within Y kilometers
of a planet.
In other words: if the crowbar pops out of FTL about six
milimeters
above the planetary defense base, the base doesn't have a
chance.
But if FTL flight is impossible within an astronomical unit or
so of a planetary mass, it is still possible to figure out some
way of getting some nasty warheads delivered to planetary
targets without significant advanced warning. It may take some
doing, though.
Here is Professor Apocalyse's patented "Catch me if you can"
relativistic warhead delivery system!
First you need space opera levels of power. Covering your
innermost planet's equator with solar cells should do.
Next you need a mass driver (some kind of magnetic linear
accelerator) parked outside of the FTL gravity limit, with
an exceedingly long extension cord plugged into
the solar cells. A power transmission laser will do in a pinch.
Just don't get in its way...
Finally, you need your warhead carrier. All it needs is
[1] one outrageously high yield warhead, [2] one FTL drive
with enough of a power source to run it, and [3]
enough computer control to run things.
Step 1: The warhead enters the mass driver at the rear, at
point "A".
Step 2: The mass driver accelerates the warhead.
Step 3: The warhead emerges from the mass driver from the front,
at point "B".
Step 4: The warhead enters FTL flight, moves from point "B" to
point "A", and leaves FTL flight.
Step 5: Go to Step 1.
Keep the warhead going through the cycle for a month or so,
and it will be moving at about 98% of the speed of light.
Actually, at this speed, the warhead becomes superfluous.
A wad of belly button lint travelling at 0.98c, penetrating
the atmosphere will generate enough gamma rays to vaporize
everything within several hundred miles and make a pool
of lava with the same radius and many hundreds of feet deep.
Now you send it to the target planet.
It pops out of FTL space at one AU from the target planet.
Transit time is about 8 minutes.
However, a funny thing happens when you try to observe
an object travelling at 0.98c with sensors using
light, radio, or other sensors that travel at c.
You can *never* see where the object *is*, you can only
see where it *was*.
Look at it this way: The warhead pops out of FTL flight
at point X. At this point it becomes visible.
Imagine a photon of light/radio/ultraviolet/whatever that
starts at point X with the warhead and is heading towards the
target planet. It is travelling at c.
The warhead also starts at point X. It is travelling at
0.98c.
The photon will arrive at the target in 8 minutes.
9.6 seconds later the warhead arrives.
So when the planetary defense base spots the warhead,
it has 9.6 seconds to react. It doesn't help to
have picket ships posted in deep orbit. Their warning
messages are unlikely to arrive any sooner, and probably
will arrive after the warhead strikes.
The picket ship cannot enter FTL and fly to the planet
because the probe emerges at the FTL limit, remember?
The planetary base's problems are not over.
How does it interdict the blasted thing?
One problem is that it can only see where the warhead was,
not where it is. If the warhead can maneuver at all,
it will be impossible to hit with an aimed shot.
And even if you hit it with a nuke, you haven't stopped it.
Now instead of a projectile travelling at 0.98c,
you have a cloud of gas travelling at 0.98c.
The cloud will do exactly the same amount of damage
to the target, it will just be diluted over a larger area.
The ground may only be molten to a depth of 200 feet instead of
500.
For more details about this depressing scenario,
find a copy of THE KILLING STAR by Charles Pelligrino and
George Zebrowski.