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# Re: [GZG] laser classes

From: Roger Books <roger.books@g...>
Date: Mon, 24 Oct 2005 15:18:29 -0400
Subject: Re: [GZG] laser classes
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_______________________________________________
Gzg-l mailing list
Gzg-l@lists.csua.berkeley.edu
http://lists.csua.berkeley.edu/mailman/listinfo/gzg-lNo, we are
calculating the chance of rolling 19 points of damage on two
dice. To do a statistical analysis on this you have to account for the
cases
where one die does not roll up 6s all the way and you have extra die
rolls
with the other.

Roger

On 10/24/05, B Lin <lin@rxkinetix.com> wrote:
>
>  Still moot, if Die A is a 3, then it's a miss. We are only
calculating
> the probability of nine 6's and a 4 or 5. If 50 dice were rolled
previous to
> this run, but none hit, it doesn't change the calculation of the 10
rolls
> that matter (i.e. dice aren't linked).
>
>  In addition, the statement was that he suffered 19 points from 2
class 1
> batteries in one turn, so the assumption was that the two batteries
> contributed to the damage, as opposed to one doing 19 and the other
none. It
> could be that one caused 4 points (2 rolls) and the other 15 points (8
> rolls), but the odds calculation doesn't change as long as the total
dice
> rolled to get that result equals ten.
>
>  There is a minor caveat in this; due to the way the FT rule is
written,
> the 6's have to come first, then the single point roll, as you only
get a
> re-roll by rolling a six. So to recreate the actual event you have to
> calculate in the order of the 9 6's first then the last die.
Statistically
> it doesn't matter which order the dice were rolled because the odds
remain
> the same.
>
>  --Binhan
>
>   ------------------------------
>
> *From:* gzg-l-bounces+lin=rxkinetix.com@lists.csua.berkeley.edu
[mailto:
> gzg-l-bounces+lin=rxkinetix.com@lists.csua.berkeley.edu] *On Behalf Of
*Roger
> Books
> *Sent:* Monday, October 24, 2005 12:31 PM
> *To:* gzg-l@lists.csua.berkeley.edu
> *Subject:* Re: [GZG] laser classes
>
>  But it could be 11 dice.
>
> 3 on die A
> 6 6 6 6 6 6 6 6 6 4:5 om Die B.
>
> Watch out for extra permutations.
>
> Roger
>
> On 10/24/05, *B Lin* <lin@rxkinetix.com> wrote:
>
> If you break down the last two rolls (the 9th six and a single point
hit
> (4 or 5) the odds are still the same whether you roll one die or two.
>
> Example: single die, chance of a 6 (1 in 6), chance of a 4 or 5 (2 in
6
> or 1 in 3) so chance of rolling a 6 plus a 4 or 5 equals 1 in 18(6 x
3)
> or rolling the other way (4 or 5 first, then a 6)= 1 in 18 (3 x 6).
For
> a total of 2 in 18 or 1 in 9.
>
> Rolling two dice - chance of rolling a combination of a 6 with a 5 or
4
> on the other die (11 chances out of 36 have a 6 (11/36) but only 4 of
> those have a 4 or 5 in them (4 of 46) final odds = 1 in 9)
>
> 6:6 (5:6)(4:6) 3:6 2:6 1:6
> (6:5) 5:5 4:5 3:5 2:5 1:5
> (6:4) 5:4 4:4 3:4 2:4 1:4
> 6:3 5:3 4:3 3:3 2:3 1:3
> 6:2 5:2 4:2 3:2 2:2 1:2
> 6:1 5:1 4:1 3:1 2:1 1:1
>
> What the calculation is 9 6's and a 4 or 5 on a single die for a total
> of 10 dice. It doesn't matter statistically which die (#1-10) rolls
the
> non-six, so using ten dice, one die or any number of dice in between
> that add up to ten doesn't matter for the calculation.
>
> --Binhan
>
> -----Original Message-----
> From: gzg-l-bounces@lists.csua.berkeley.edu
> [mailto:gzg-l-bounces@lists.csua.berkeley.edu] On Behalf Of McCarthy,
> Tom
> Sent: Monday, October 24, 2005 11:20 AM
> To: gzg-l@lists.csua.berkeley.edu
> Subject: RE: [GZG] laser classes
>
> I just meant that two dice lets you have a bad roll in the mix.
>
> 2 dice, for example, let's you roll: 6,6; 6,6; 6,2; 6; 6; 6; 6; 4 or
> 6,6; 6,6; 6,1; 6; 6; 6; 6; 4 or 6,6; 6,6; 6,4; 6; 6; 6; 6; 1 and still
> reach 19.
>
> Of course, if you are firm in your belief that you are as likely to
> reach 19 points of damage with 1 die as you are with multiple dice,
then
> I really have no argument to counter that.
>
> > -----Original Message-----
> > From: gzg-l-bounces+tom.mccarthy=xwave.com@lists.csua.berkeley.edu
> > [mailto:
gzg-l-bounces+tom.mccarthy=xwave.com@lists.csua.berkeley.edu]
> On
> > Behalf Of B Lin
> > Sent: Monday, October 24, 2005 1:11 PM
> > To: gzg-l@lists.csua.berkeley.edu
> > Subject: RE: [GZG] laser classes
> >
> > It actually doesn't make any difference whether you use one die or
two
> > or ten -
> > For example:
> > 1 die - chance to roll a 6 = 1 in 6, chance to roll two sixes 1 in
36
> (1
> > in 6 x 1 in 6)
> > 2 dice - chance to roll two sixes, 1 in 36.
> >
> > You can either roll a single die ten times or roll ten dice once
each
> > and the odds are exactly the same. Remember dice have no memory and
> are
> > not linked to each other (in theory) so one die's result is not
> affected
> > by the result of a previous roll, a future roll or neighboring die's
> > roll.
> >
> > --Binhan
> >
> > -----Original Message-----
> > From: gzg-l-bounces@lists.csua.berkeley.edu
> > [mailto: gzg-l-bounces@lists.csua.berkeley.edu] On Behalf Of
McCarthy,
> > Tom
> > Sent: Monday, October 24, 2005 10:48 AM
> > To: gzg-l@lists.csua.berkeley.edu
> > Subject: RE: [GZG] laser classes
> >
> > For 6 to the 9th, I get 10,077,696. That makes the odds of getting
> > exactly 19 points on one die to be 1 in 30,233,088 or so. On two
> dice,
> > it's more likely, but still pretty unlikely.
> >
> >
> > _______________________________________________
> > Gzg-l mailing list
> > Gzg-l@lists.csua.berkeley.edu
> > http://lists.csua.berkeley.edu/mailman/listinfo/gzg-l
> >
> > _______________________________________________
> > Gzg-l mailing list
> > Gzg-l@lists.csua.berkeley.edu
> > http://lists.csua.berkeley.edu/mailman/listinfo/gzg-l
>
>
> _______________________________________________
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>
> _______________________________________________
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> http://lists.csua.berkeley.edu/mailman/listinfo/gzg-l
>
>
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>

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