RE: [GZG] laser classes

If you break down the last two rolls (the 9th six and a single point hit
(4 or 5) the odds are still the same whether you roll one die or two.

Example: single die, chance of a 6 (1 in 6), chance of a 4 or 5 (2 in 6
or 1 in 3) so chance of rolling a 6 plus a 4 or 5 equals 1 in 18(6 x 3)
or rolling the other way (4 or 5 first, then a 6)= 1 in 18 (3 x 6). For
a total of 2 in 18 or 1 in 9.

Rolling two dice - chance of rolling a combination of a 6 with a 5 or 4
on the other die (11 chances out of 36 have a 6 (11/36) but only 4 of
those have a 4 or 5 in them (4 of 46) final odds = 1 in 9)

 6:6 (5:6)(4:6)  3:6  2:6  1:6
(6:5) 5:5  4:5	3:5  2:5  1:5
(6:4) 5:4  4:4	3:4  2:4  1:4
 6:3  5:3  4:3	3:3  2:3  1:3
 6:2  5:2  4:2	3:2  2:2  1:2
 6:1  5:1  4:1	3:1  2:1  1:1

What the calculation is 9 6's and a 4 or 5 on a single die for a total
of 10 dice. It doesn't matter statistically which die (#1-10) rolls the
non-six, so using ten dice, one die or any number of dice in between
that add up to ten doesn't matter for the calculation.

--Binhan

-----Original Message-----
From: gzg-l-bounces@lists.csua.berkeley.edu
[mailto:gzg-l-bounces@lists.csua.berkeley.edu] On Behalf Of McCarthy,
Tom
Sent: Monday, October 24, 2005 11:20 AM
To: gzg-l@lists.csua.berkeley.edu
Subject: RE: [GZG] laser classes

I just meant that two dice lets you have a bad roll in the mix.

2 dice, for example, let's you roll: 6,6; 6,6; 6,2; 6; 6; 6; 6; 4 or
6,6; 6,6; 6,1; 6; 6; 6; 6; 4 or 6,6; 6,6; 6,4; 6; 6; 6; 6; 1 and still
reach 19.

Of course, if you are firm in your belief that you are as likely to
reach 19 points of damage with 1 die as you are with multiple dice, then
I really have no argument to counter that.

> -----Original Message-----
> From: gzg-l-bounces+tom.mccarthy=xwave.com@lists.csua.berkeley.edu
> [mailto:gzg-l-bounces+tom.mccarthy=xwave.com@lists.csua.berkeley.edu]
On
> Behalf Of B Lin
> Sent: Monday, October 24, 2005 1:11 PM
> To: gzg-l@lists.csua.berkeley.edu
> Subject: RE: [GZG] laser classes
> 
> It actually doesn't make any difference whether you use one die or two
> or ten -
> For example:
> 1 die - chance to roll a 6 = 1 in 6, chance to roll two sixes 1 in 36
(1
> in 6 x 1 in 6)
> 2 dice - chance to roll two sixes, 1 in 36.
> 
> You can either roll a single die ten times or roll ten dice once each
> and the odds are exactly the same.  Remember dice have no memory and
are
> not linked to each other (in theory) so one die's result is not
affected
> by the result of a previous roll, a future roll or neighboring die's
> roll.
> 
> --Binhan
> 
> -----Original Message-----
> From: gzg-l-bounces@lists.csua.berkeley.edu
> [mailto:gzg-l-bounces@lists.csua.berkeley.edu] On Behalf Of McCarthy,
> Tom
> Sent: Monday, October 24, 2005 10:48 AM
> To: gzg-l@lists.csua.berkeley.edu
> Subject: RE: [GZG] laser classes
> 
> For 6 to the 9th, I get 10,077,696.  That makes the odds of getting
> exactly 19 points on one die to be 1 in 30,233,088 or so.  On two
dice,
> it's more likely, but still pretty unlikely.
> 
> 
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