RE: [SG2] Points

You also need to consider the other side of the equation; how many hits
can
it absorb before destruction?
If you only have a squad of two, even a single casualty is a major
problem.
It's more likely to take 2 or 3 casualties (FP 1d8+1d8 SAW + QD d8 =
average
13-14) at either d6 or d8 range.  50% chance of killing half your squad
outright (less armor:impact chance) or losing both at once.  With a
larger
squad, as the battle shifts around (and you re-organise squads and shift
casualties to medevacs) you still have a viable unit.

Suppressions can be removed given enough time, but death is permanent
(hence
why I have about 20 body bag figures...)

If you use 2 man squads, it makes little difference whether you use FP2
assault rifles or FP0.5 Lee Enfields; the minimum for squad fire is a d4
(in
fact the Lee Enfields would be better, as you get a higher impact die)

Brendan
'Neath Southern Skies

> -----Original Message-----
> From: Laserlight [SMTP:laserlight@quixnet.net]
> Sent: Friday, March 12, 2004 4:02 PM
> To:	gzg-l@csua.berkeley.edu
> Subject:	[SG2]  Points
> 
> 
> Thinking about squad sizes: given 6 troops with FP2 weapons and QD8, 
> what is the most efficient way to arrange them?
> 
> Part one is "doing damage".  To summarize the arithmetic, the odds are

> as follows.  For the first two arrangements, totals do not add up to 
> 100% because oof overlapping between hits and suppressions.
> 
> A: Three teams of 2 soldiers (FP4):
>	Complete miss: 9.48
>	At least one suppression: 84.1
>	At least one hit: 14.48
> 
> B: Two teams of 3 soldiers (FP6)
>	Complete miss: 14.9%
>	At least one suppression= 72.7%
>	At least one hit = 25.6%
> 
> C: One team of 6 soldiers (FP12)
>	Complete miss = 21.1%
>	Suppression = 51.6%
>	Hit = 27.4%
> 
> Two factors I havent analyzed yet: given that multiple teams may
inflict 
> multiple hits, what's the average number of hits inflicted?  And given

> that they're rolling different size dice to hit and the way SG 
> calculates "number of casualties", what is the average number of 
> casualties per "hit" (it's not just the average of the two dice
because, 
> for instance, a 1 on either die means you didn't hit)?
>	
> 
> 
> 
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