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Re: [FT] [computer] 3D math

From: Tony Francis <tony.francis@k...>
Date: Mon, 11 Sep 2000 10:33:49 +0100
Subject: Re: [FT] [computer] 3D math
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"Barclay, Tom" wrote:

> Hiya
>
> I'm looking for a non-horrendous formula for calculating, given the
> following facts,
>
> - in 3 space
> - a sphere we shall call S1 located at coorinates (x1,y1,z1) of radius
r1.
> - a sphere we shall call S2 located at coorinates (x2,y2,z2) of radius
r2.
> - a point we shall call P3 located at coordinates (x3,y3,z3).
>
> A) Do r1 and r2 intersect one another? What formula will determine
this?
>
> <My guess: Take a line between the centre of S1 and S2 and determine
if the
> length of this segment exceeds the sum of the radii r1 and r2>.

Correct. Distance between the sphere centres (d) is equal to

d = sqrt ((x2 - x1)^2 + (y2 - y1)^2 + (z2 - z1)^2)

If this distance is less than (r1 + r2) then the spheres intersect.

If you want a faster version then don't perform the square root
calculation on

d^2 < (r1 + r2)^2

This is a trick I use a lot of the time so save unnecessary square root
calls
(which are very computationally expensive).

> B) Is point P3 within sphere S1?
>
> <My guess here is take the magnitude of the line between the centre of
S1
> and P3 and if it is <= radius r1 then P3 is inside of S1>.
>

Correct again, but you can use the same trick as above by not finding
the root
of the line between S1 and P3.

Tony
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