Re: [FT] A thought on that vector movement problem

Donald Hosford 

> I may be unsure about this, (my FB copy is at a friend's house)  but
the 
> way I  understand it, any thrust used to maneuver, is taken from the 
> "main" thrust.

Only in Cinematic movement. In Vector, main and maneuver thrusters are
separate.

Tim wrote in reply to... Firefall, IIRC:
 
> >Thus if you do MD 6, rotate 90 degrees and 
> >push 2, you've used 100% of your turn for Main Drive + 100% for your 
> >Thruster  = 200%.
> 
> According to FB they are separate systems so its 100% of each as 
> stated above, but 100% of your total combined propulsion system (drive
> + thrusters) not 200%.

You misunderstand. What the previous poster said was this:

Your ship has MD 6 and Thruster 3.

First you burn your main drive the entire turn, and increase your speed
by 6.

At the end of the turn, you turn 90 degrees (or 180, it doesn't matter).

Then, still at the end of the turn, you do *another*FULL*turn* of
maneuver thrust, and increase your velocity by another 3. 

So, you haven't used more than 100% of the total thrust power of the
ship, but you have used up 200% of the *time* available in a single game
turn - unless, of course, your ship manages to face in two separate
directions at once (but if it does, I'd say it is badly broken <g>).

This is the problem the discussion is all about.

Oerjan Ohlson
oerjan.ohlson@telia.com

"Life is like a sewer.
  What you get out of it, depends on what you put into it."
- Hen3ry