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Date: Mon, 24 Oct 2005 11:54:52 -0600

Subject: RE: [GZG] laser classes

```
If you break down the last two rolls (the 9th six and a single point hit
(4 or 5) the odds are still the same whether you roll one die or two.
Example: single die, chance of a 6 (1 in 6), chance of a 4 or 5 (2 in 6
or 1 in 3) so chance of rolling a 6 plus a 4 or 5 equals 1 in 18(6 x 3)
or rolling the other way (4 or 5 first, then a 6)= 1 in 18 (3 x 6). For
a total of 2 in 18 or 1 in 9.
Rolling two dice - chance of rolling a combination of a 6 with a 5 or 4
on the other die (11 chances out of 36 have a 6 (11/36) but only 4 of
those have a 4 or 5 in them (4 of 46) final odds = 1 in 9)
6:6 (5:6)(4:6) 3:6 2:6 1:6
(6:5) 5:5 4:5 3:5 2:5 1:5
(6:4) 5:4 4:4 3:4 2:4 1:4
6:3 5:3 4:3 3:3 2:3 1:3
6:2 5:2 4:2 3:2 2:2 1:2
6:1 5:1 4:1 3:1 2:1 1:1
What the calculation is 9 6's and a 4 or 5 on a single die for a total
of 10 dice. It doesn't matter statistically which die (#1-10) rolls the
non-six, so using ten dice, one die or any number of dice in between
that add up to ten doesn't matter for the calculation.
--Binhan
-----Original Message-----
From: gzg-l-bounces@lists.csua.berkeley.edu
[mailto:gzg-l-bounces@lists.csua.berkeley.edu] On Behalf Of McCarthy,
Tom
Sent: Monday, October 24, 2005 11:20 AM
To: gzg-l@lists.csua.berkeley.edu
Subject: RE: [GZG] laser classes
I just meant that two dice lets you have a bad roll in the mix.
2 dice, for example, let's you roll: 6,6; 6,6; 6,2; 6; 6; 6; 6; 4 or
6,6; 6,6; 6,1; 6; 6; 6; 6; 4 or 6,6; 6,6; 6,4; 6; 6; 6; 6; 1 and still
reach 19.
Of course, if you are firm in your belief that you are as likely to
reach 19 points of damage with 1 die as you are with multiple dice, then
I really have no argument to counter that.
> -----Original Message-----
> From: gzg-l-bounces+tom.mccarthy=xwave.com@lists.csua.berkeley.edu
> [mailto:gzg-l-bounces+tom.mccarthy=xwave.com@lists.csua.berkeley.edu]
On
> Behalf Of B Lin
> Sent: Monday, October 24, 2005 1:11 PM
> To: gzg-l@lists.csua.berkeley.edu
> Subject: RE: [GZG] laser classes
>
> It actually doesn't make any difference whether you use one die or two
> or ten -
> For example:
> 1 die - chance to roll a 6 = 1 in 6, chance to roll two sixes 1 in 36
(1
> in 6 x 1 in 6)
> 2 dice - chance to roll two sixes, 1 in 36.
>
> You can either roll a single die ten times or roll ten dice once each
> and the odds are exactly the same. Remember dice have no memory and
are
> not linked to each other (in theory) so one die's result is not
affected
> by the result of a previous roll, a future roll or neighboring die's
> roll.
>
> --Binhan
>
> -----Original Message-----
> From: gzg-l-bounces@lists.csua.berkeley.edu
> [mailto:gzg-l-bounces@lists.csua.berkeley.edu] On Behalf Of McCarthy,
> Tom
> Sent: Monday, October 24, 2005 10:48 AM
> To: gzg-l@lists.csua.berkeley.edu
> Subject: RE: [GZG] laser classes
>
> For 6 to the 9th, I get 10,077,696. That makes the odds of getting
> exactly 19 points on one die to be 1 in 30,233,088 or so. On two
dice,
> it's more likely, but still pretty unlikely.
>
>
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